Digit Sum with while

Lab C++ Beginner 10 points

Read a non-negative integer and print the sum of its digits.

Input

One integer.

Output

The digit sum.

Example

Input

Output

Sample input available Sample output available

Editor

C++

Hints

n % 10 is the last digit; n /= 10 drops it.

Solution explanation

A while loop fits when you don't know the number of iterations in advance.

Show solution

#include <iostream>
using namespace std;

int main() {
    long long n;
    cin >> n;
    int sum = 0;
    while (n > 0) {
        sum += n % 10;
        n /= 10;
    }
    cout << sum << "\n";
    return 0;
}

Output

Answer