Coin Change (DP)
Completed
Read coin values and an amount. Print the minimum number of coins needed to make the amount, or -1 if impossible.
Input
Line 1: coin values. Line 2: amount.
Output
One integer.
Example
Input
1 2 5 11
Output
3
Editor
Python
Hints
best[v] = fewest coins for value v.
best[v] = min over coins c of best[v - c] + 1.
Solution explanation
Dynamic programming builds the answer for every smaller amount first and reuses it.
Show solution
coins = list(map(int, input().split()))
amount = int(input())
INF = float("inf")
best = [0] + [INF] * amount
for value in range(1, amount + 1):
for c in coins:
if c <= value and best[value - c] + 1 < best[value]:
best[value] = best[value - c] + 1
print(best[amount] if best[amount] != INF else -1)