Gradebook Report

Lab Python Advanced 30 points

Read n lines name score score .... Print a table: name left-aligned in 10 characters, average right-aligned in 6 with 1 decimal, and a grade (A ≥ 90, B ≥ 75, C ≥ 50, else F). Sort by average descending, then name. Finish with class average: X.

Input

Line 1: n. Then n lines.

Output

n + 1 lines.

Example

Input

3
ann 90 95 100
bob 70 80
cy 40 60 50

Output

ann         95.0 A
bob         75.0 B
cy          50.0 C
class average: 73.3

Sample input available Sample output available

Editor

Python

Hints

Collect (name, average) tuples, then sort them.

A loop over (limit, letter) pairs avoids repeated elifs.

Solution explanation

Separating the calculation (grade) from the presentation keeps the program readable.

Show solution

def grade(avg):
    for limit, letter in ((90, "A"), (75, "B"), (50, "C")):
        if avg >= limit:
            return letter
    return "F"


rows = []
for _ in range(int(input())):
    name, *scores = input().split()
    scores = list(map(int, scores))
    rows.append((name, sum(scores) / len(scores)))

for name, avg in sorted(rows, key=lambda r: (-r[1], r[0])):
    print(f"{name:<10}{avg:>6.1f} {grade(avg)}")
print(f"class average: {sum(a for _, a in rows) / len(rows):.1f}")

Output

Answer