Challenge: The Oldest Person

Lab C Intermediate 20 points

Read n, then n people as name age. Store them in an array of structs and print the name of the oldest person (if there is a tie, the first one wins) and the average age with 1 decimal.

Input

n (1 ≤ n ≤ 50), then n lines of a name and an age.

Output

Oldest: NAME
Average age: X.X

Example

Input

3
Asha 31
Bo 45
Cy 22

Output

Oldest: Bo
Average age: 32.7

Sample input available Sample output available

Editor

Hints

Keep the index of the oldest person so far.

Use > (not >=) so the first one wins a tie.

Solution explanation

One loop reads every person, adds up the ages and tracks who is oldest.

Show solution

#include <stdio.h>

typedef struct {
    char name[30];
    int age;
} Person;

int main() {
    int n;
    Person people[50];
    scanf("%d", &n);
    int total = 0;
    int oldest = 0;
    for (int i = 0; i < n; i++) {
        scanf("%s %d", people[i].name, &people[i].age);
        total += people[i].age;
        if (people[i].age > people[oldest].age) {
            oldest = i;
        }
    }
    printf("Oldest: %s\n", people[oldest].name);
    printf("Average age: %.1f\n", (double) total / n);
    return 0;
}

Output

Answer