Challenge: Shopping Bill

Lab C Intermediate 20 points

Read n, then n items as name quantity price (price is a decimal). Print each item's line total as name: total with 2 decimals, then the grand total. If the grand total is more than 100, take 10% off and also print the discounted total.

Input

n (1 ≤ n ≤ 20), then n lines of a name, a whole number and a decimal.

Output

One line per item, then Total: X.XX, and if it applies, After discount: Y.YY.

Example

Input

3
bread 2 1.5
milk 1 0.99
eggs 12 0.25

Output

bread: 3.00
milk: 0.99
eggs: 3.00
Total: 6.99

Sample input available Sample output available

Editor

Hints

Read the price with %lf.

Line total = quantity * price.

10% off means multiplying by 0.9.

Solution explanation

Each line total is printed as we go and added to a running total, which decides the discount at the end.

Show solution

#include <stdio.h>

typedef struct {
    char name[30];
    int quantity;
    double price;
} Item;

int main() {
    int n;
    Item items[20];
    scanf("%d", &n);
    double total = 0;
    for (int i = 0; i < n; i++) {
        scanf("%s %d %lf", items[i].name, &items[i].quantity, &items[i].price);
        double line = items[i].quantity * items[i].price;
        printf("%s: %.2f\n", items[i].name, line);
        total += line;
    }
    printf("Total: %.2f\n", total);
    if (total > 100) {
        printf("After discount: %.2f\n", total * 0.9);
    }
    return 0;
}

Output

Answer