Challenge: Sum with a Pointer

Lab C Intermediate 20 points

Read n and n numbers into an array. Then add them up by walking through the array with a pointer (int *p = nums; and p++), and print the total.

Input

n (1 ≤ n ≤ 100), then n integers.

Output

The total.

Example

Input

4
1 2 3 4

Output

Sample input available Sample output available

Editor

Hints

Start with int *p = nums;

*p is the current number; p++ moves to the next one.

Solution explanation

Each p++ moves the pointer one item forward, so *p visits every number in turn.

Show solution

#include <stdio.h>

int main() {
    int n;
    int nums[100];
    scanf("%d", &n);
    for (int i = 0; i < n; i++) {
        scanf("%d", &nums[i]);
    }
    int *p = nums;
    int total = 0;
    for (int i = 0; i < n; i++) {
        total += *p;
        p++;
    }
    printf("%d\n", total);
    return 0;
}

Output

Answer