The nextLine Trap

Lab Java Intermediate 20 points

Read an age (integer) on the first line and a full name on the second line. Print NAME is AGE. Beware: nextInt() leaves the line break behind.

Input

Line 1: age. Line 2: full name.

Output

One line.

Example

Input

30
Grace Hopper

Output

Grace Hopper is 30
Sample input available Sample output available
Editor
Java

Hints

After nextInt(), call nextLine() once to skip the end of that line.

Solution explanation

This is the most common Scanner bug: without the extra nextLine() you'd read an empty name.

Show solution
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int age = sc.nextInt();
        sc.nextLine(); // consume the rest of the first line
        String name = sc.nextLine();
        System.out.println(name + " is " + age);
    }
}
Output
Answer
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