Pass by Value

Lab Java Intermediate 20 points

Write static void addOne(int x) that adds 1 to its parameter, and static void addOneAll(int[] a) that adds 1 to every element. Read a number and an array, call both, and print the number and the array.

Input

Line 1: a number. Line 2: n. Line 3: n integers.

Output

Two lines: the (unchanged) number, then the changed array.

Example

Input

5
3
1 2 3

Output

5
[2, 3, 4]

Sample input available Sample output available

Editor

Java

Hints

Java always passes a copy of the value.

For an array, the copied value is a reference to the same array.

Solution explanation

Changing a primitive parameter never affects the caller; changing an array's contents does, because both refer to the same array.

Show solution

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    static void addOne(int x) {
        x++;
    }

    static void addOneAll(int[] a) {
        for (int i = 0; i < a.length; i++) {
            a[i]++;
        }
    }

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int number = sc.nextInt();
        int n = sc.nextInt();
        int[] a = new int[n];
        for (int i = 0; i < n; i++) {
            a[i] = sc.nextInt();
        }
        addOne(number);
        addOneAll(a);
        System.out.println(number);
        System.out.println(Arrays.toString(a));
    }
}

Output

Answer